Plastic Deformation of Thick Hollow Sphere with Internal Pressure.
This accuracy verification example demonstrates the reliability of the event simulation solver in quantifying the following three phenomena:
The model is a one-sixteenth symmetry representation of a thick-walled hollow sphere. A uniform pressure is applied to the interior cavity surface. The pressure magnitude is ramped up linearly. At some point in the event, plastic deformation begins to occur at the interior surface. As the event simulation continues, more of the wall thickness reaches plastic stress levels progressively. Eventually, the outer surface reaches the yield stress, at which point the sphere begins to expand rapidly. The derivation of the pressures required to just reach the plastic state at the interior and exterior surfaces is shown on this page. The Fusion results are compared to the theoretical results.
A perfectly plastic material is assumed, meaning that the slope of the stress-strain curve is flat (zero) once yield occurs. In other words, there is no work hardening of the material. This assumption makes the theoretical derivation simpler.
Frictionless constraints represent the symmetry conditions at each sliced (flat) surface of the hollow sphere.
Strain | Stress – psi (kPa) |
---|---|
0.0 | 0.0 |
0.0012 | 36,000 (248,211) |
0.5 | 36,000 (248,211) |
Time | Magnitude |
---|---|
0.0 | 0.0 |
0.051 | 51,000 |
We consider solutions for the two limit cases as plasticity progresses from the inside surface to the outside surface:
We calculate two variables—the radial displacement of the inside surface (δi) in inches and the applied pressure (P) in psi.
Where:
Fusion interpolates results between the solver's output increments. The pressure at which the model just achieves a 36,000 psi stress level can be determined using the 2D Chart of the maximum von Mises Stress results. As closely as possible, locate the point along the graph where the stress level first reaches 36,000 psi. Zoom in for better resolution when dragging the crosshair over the graph. To zoom, click and drag over the critical portion of the graph. The Case 1 step is approximately 21.04. The pressure increases 1,000 psi per step. Therefore, the applied pressure for Case 1 = 21.04 * 1,000 psi = 21,040 psi.
Display the Total Displacement results for the same step. Because of the geometry, all displacements are radial, and the maximum displacement occurs at the inside surface throughout the event.
The pressure at which full plasticity is achieved is determined by looking at the 2D Chart of the maximum Total Displacement results. Determine the step at which the maximum displacement is on the verge of increasing rapidly. (Once full plasticity is achieved, there's nothing to prevent the rapid expansion of the sphere.) This condition occurs approximately at step 50.00. The displacement is increasing very gradually up to this step. From step 50.0001 upward, the rate of change is markedly increased. Therefore, the applied pressure for Case 2 = 50 * 1,000 psi = 50,000 psi., and the plot legend shows the corresponding displacement.
Case Number | Applied Pressure (psi): | Radial Displacement (inches): | ||||
---|---|---|---|---|---|---|
Theory | Fusion | % Difference | Theory | Fusion | % Difference | |
1 | 21,000 | 21,040 | 0.19 % | 0.001116 | 0.001116 | -0.00 % |
2 | 49,906.6 | 50,000 | 0.19 % | 0.0122346 | 0.01185 | -3.14 % |
Chakrabarty, J., Theory of Plasticity, McGraw-Hill, New York, 1987, pages 307-311.